RE: [xsl] Multiple search and replace

["Pankaj Chaturvedi" <pankaj.chaturvedi@xxxxxxxxx>]

I tried it but was not working ........ now I know why.....updating the
wrong stylesheet (using 3 stylesheets in my project)... He! He!.....I am
having one of those days.

Thanks Michael.


-----Original Message-----
From: Michael Kay [mailto:mike@xxxxxxxxxxxx]
Sent: Thursday, April 03, 2008 5:01 PM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: RE: [xsl] Multiple search and replace


You want $1 rather than \1 to refer to group 1 in the replace string.

Michael Kay
http://www.saxonica.com/

> -----Original Message-----
> From: Pankaj Chaturvedi [mailto:pankaj.chaturvedi@xxxxxxxxx]
> Sent: 03 April 2008 19:23
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: RE: [xsl] Multiple search and replace
>
> Hi,
>
>     <xsl:sequence select="replace(., '\[#x(\d+)\]',
> '&#xE000;#x\1;')" />
>
> Gives error: invalid replace string. The problem I believe is
> at group \1, though I do not see any wrong in regex syntax.
> May be some problem with "Built-in XSLT engine" of XMLSpy.
>
> It seems I need to install java in my system to use Saxon 9
> processor. Any ideas.
>
>
>
>
>
> -----Original Message-----
> From: Abel Braaksma [mailto:abel.online@xxxxxxxxx]
> Sent: Wednesday, April 02, 2008 12:03 PM
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: Re: [xsl] Multiple search and replace
>
>
> Hi Pankaj,
>
> see my comments below:
>
>
> Pankaj Chaturvedi wrote:
> > Hi all,
> >
> > I am trying to define multiple search and replace in style sheet.
> >
>
> first thought: consider using XSLT 2.0, which has search and
> replace built in using the replace() function which can
> handle regular expression style search and replace in one call.
>
> > Basically trying to convert [#x02010] (and other Unicode values) to
> > their corresponding values &#x02010; .
> >
>
> Second thought consider using XSLT 2.0: getting the numeric
> value of a character can be done using string-to-codepoints,
> which is not available in XSLT 1.0. Second thought (b):
> sorry, I see that you mean the literal string '[#...]'....
>
> > Below is what I am trying to do:
> >
> > <snip />
> >
> > I have two questions in regard:
> >
> > 1. I am bound to define & as &amp; as XMLSpy giving an error
> > "character is grammatically unexpected". Is there other way of
> > overcoming this issue and get & in output.
> >
>
> Not doing something because your tool limits you is very dangerous...
> However, in this case, XMLSpy is correct. The underlying technology
> (XML) does not allow a literal &amp;, simply because XSLT
> *is* XML and XML does not allow it. However, if you output as
> text, the serializer will output '&' when you put &amp; somewhere.
>
> Third thought: use XSLT 2.0. It has the ability to add character maps.
> In a character map you can say that some character, say '$'
> (but using something from the Private Area Unicode ranges is
> recommended) can be mapped to some string. Using character
> maps you can get a literal '&' in the output.
>
> > 2. I also need to replace "]" to  ";" for which I was
> trying to call
> > the another template with in <xml:template match="text()"> as below
> > but
> doesn't
> > seems to be working.
> >
> > <snip />
> > Can we do multiple search and replaces in one named
> template or do I
> > need
> to
> > define them all separately (I need to call all of them in
> one template
> > <xsl:template match="text()">).
> >
>
> XSLT is a functional language. You will have to call the
> replace function recursively. I believe there's an example on
> the exslt.org site which shows how you  can do this for a
> multiple search and replace in a generic way.
>
> Fourth thought: use XSLT 2.0. All you'll end up with then is a nested
> replace(replace(....)) call.
>
> Fifth thought: use XSLT 2.0 for the whole shebang. Your whole
> solution will look like this:
>
> <xsl:output use-character-maps="searchreplace" />
>
> <xsl:character-map name="searchreplace">
>     <xsl:output-character character="&#xE000;" string="&amp;"
> /> </xsl:character>
>
> <xsl:template match="text()">
>     <xsl:sequence select="replace(., '\[#(\d+)\]',
> '&#xE000;#x\1;')" /> </xsl:template>
>
>
> Sixth thought: use XSLT 2.0. You seem to be using XMLSpy,
> which can handle XSLT 2.0. However, its engine is a bit
> flaky. If you run into problems, consider using either
> Gestalt XSLT 2.0 or Saxon XSLT 2.0 processors.
>
> Note: you may think that putting &amp; inside the
> string-attribute of xsl:output-character creates &amp; in the
> output, but this is not true.
> Since XSLT is XML, you must put &amp; there. But to get the
> translation to serialize to literal &amp; instead means
> double escaping: "&amp;amp;"
> (but that is not what you are after here). Understanding the
> implications of using character references in XML is vital of
> headache-free working with XML and XSLT (plus all other XML
> related technologies in fact), but it can be hard at times to
> get it right in your head.
>
> Hope this helps,
>
> Cheers,
> -- Abel Braaksma
>
>
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