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Re: [xsl] adding hierarchy

Subject: Re: [xsl] adding hierarchy
From: Florent Georges <lists@xxxxxxxxxxxx>
Date: Thu, 3 Apr 2008 20:04:08 +0200 (CEST)
Jim_Albright@xxxxxxxxxxxx wrote:

  Hi

> <xsl:template match="item[following::*[1]=following::list[1]]">

  If you want to test if the following element is a 'list', use
instead:

    item[following::*[1][self::list]]

>         <xsl:element name="item">

  This is not an error, but this is usually easier to read when you use
literal elements:

    <item>

  Regards,

--drkm






















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