Subject: Re: [xsl] Extracting value from node with formatter elements From: "Vyacheslav Sedov" <vyacheslav.sedov@xxxxxxxxx> Date: Mon, 14 Apr 2008 17:30:29 +0400 |
use <xsl:copy-of select="."/> On Mon, Apr 14, 2008 at 5:22 PM, Amit Hanchinamani <a.hanchinamani@xxxxxxxxxxx> wrote: > Hi All, > > I am using XSLT 2.0 and parser Saxon. > > I am transforming some html tags to another tag format. I have span tags > which contain text value surrounded by formattere like bold, italic and > underline. The problem is when I try to extract the value of the node, it > always returns the text value without formatters <b>,<u> & <i>. The > following is the code: > > <xsl:template match="span" mode="copy"> > <xsl:variable name="elementText"> > <xsl:value-of select="." /> > </xsl:variable> > > The input tag looks the following > <span style="font-family:Times New Roman;font-size:12.0pt;"><b><u>blah > blah</u></b></span> > > I want to get the entire node value "<b><u>blah blah</u></b>". But using > <xsl:value-of select="." /> or <xsl:value-of select="text()"/> or > <xsl:value-of select="current()" /> returns only "blah blah". I cannot > figure out how to get the entire value along with the formatting tags. > Any help appreciated. > > Regards, > Amit > > > .
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