Re: [xsl] named template with parameter problem

["Ilya Lifshits" <chehlo@xxxxxxxxx>]

Thanks, it's worked.

On Wed, Apr 23, 2008 at 12:10 AM, Scott Trenda <Scott.Trenda@xxxxxxxx> wrote:
> Did you mean to pass the string 'utt_chp9_ifc_desc'? The
>  <xsl:with-param> is looking for a child element with name
>  utt_chp9_ifc_desc, which doesn't exist. Wrap quotes around
>  'utt_chp9_ifc_desc' if you're intending a string.
>
>  ~ Scott
>
>
>
>
>  -----Original Message-----
>  From: Ilya Lifshits [mailto:chehlo@xxxxxxxxx]
>  Sent: Tuesday, April 22, 2008 4:08 PM
>  To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
>  Cc: Ilya Lifshits
>  Subject: [xsl] named template with parameter problem
>
>  Hi all,
>
>  I have problem with parameters in named template.
>
>
>  snippet from xsl file
>  --------
>  <xsl:template name="j_test_ref">
>     <xsl:param name="m_id"/>
>     <xsl:param name="t_id"/>
>     <xsl:param name="link"/>
>
>     T.<xsl:value-of select='$m_id'/>.<xsl:value-of select='$t_id'/>
>     <xsl:element name="xref">
>         <xsl:attribute name="xrefstyle">select:
>  labelnumber</xsl:attribute>
>         <xsl:attribute name="linkend"><xsl:value-of
>  select='$link'/></xsl:attribute>
>     </xsl:element>
>  </xsl:template>
>
>
>  <xsl:template match="j_interface_desc_test_ref">
>     Interface Descriptor test -
>     <xsl:call-template name="j_test_ref">
>         <xsl:with-param name="m_id" select='1'/>
>         <xsl:with-param name="t_id" select='4'/>
>         <xsl:with-param name="link" select='utt_chp9_ifc_desc'/>
>     </xsl:call-template>
>  </xsl:template>
>
>  input xml file
>  --------------
>
>  <j_interface_desc_test_ref/>
>
>
>  output xml file
>  ---------------
>
>  T.1.4<xref xrefstyle="select: labelnumber" linkend=""/>
>
>  expected result
>
>  T.1.4<xref xrefstyle="select: labelnumber" linkend="utt_chp9_ifc_desc"/>
>
>  For some reason link parameter is not passed correctly to the
>  j_test_ref template.
>  I probably missed something simple.
>
>  Thanks for advice
>  Ilya.