RE: [xsl] fallback to a default template in xsl processing

["Daly, April" <april@xxxxxxxxxxx>]

Hi,
Thank you!

I tried that and maybe I didn't set it up correctly....buts the nodes with
'named' templates (e.g., 'A' or 'B') were processed twice, once by the
template with match='A' and the other by match='*'.
Thanks for your help!
Regards,

April
April L Daly
Daly Web, Inc.
________________________________________
From: Jim Earley [xml.jim@xxxxxxxxx]
Sent: Thursday, April 24, 2008 3:38 PM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: RE: [xsl] fallback to a default template in xsl processing

One approach for this is to use the following:

<xsl:template match="*">
  ...
</xsl:template>

Jim Earley
XML Architect
Flatirons Solutions Corp.



-----Original Message-----
From: Daly, April [mailto:april@xxxxxxxxxxx]
Sent: Thursday, April 24, 2008 1:29 PM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: [xsl] fallback to a default template in xsl processing

Hi!

I have what I hope is a simple question for the xsl/xpath gurus!


I would like to be able to apply a default template within xsl 1.0 if no match
is found.
Currently I'm using an ugly  'brute-force' approach using <xsl:choose>:

<xsl:choose>
   <xsl:when test="name()='A' or name()='B'">
      <xsl:apply-templates mode='namedTemplates' select='.'/>
   </xsl:when>
   <xsl:otherwise>
      <xsl:apply-templates mode='defaultTemplates' select='.'/>
   </xsl:otherwise>
</xsl:choose>


this is a simplfied example, but I hope it shows what I'm trying to do.

Is there a better way to apply a named template if 'found' otherwise apply a
default
template?

Thanks (in advance) for your help!

April
April L Daly
Daly Web, Inc.