Re: [xsl] Combine two diff xmls - Sorting by date

[Martin Honnen <Martin.Honnen@xxxxxx>]

sudheshna iyer wrote:

> > From xsl of File2.xml:
> 	 <xsl:apply-templates select="* |
> document('File3.xml')/*"/>  ==> IS THIS CORRECT?
> Step3: Now File2Xsl contains File2.xml and File3.xml
>
> Step4: But when I process combined XML, each XML is
> getting processed as two files. I
> am not seeing one x

I think you should be able to do
  <xsl:apply-templates
    select="/Announcements/announcement | 
document('File3.xml')/Annoucements/announcement">
    <xsl:sort select="translate(anc_date, '-', '')"
              data-type="number"
              order="descending"/>
  </xsl:apply-templates>




--

	Martin Honnen
	http://JavaScript.FAQTs.com/