Re: [xsl] Directory listing, as xml file

["bryan rasmussen" <rasmussen.bryan@xxxxxxxxx>]

That depends too much on your platform to say. Is this XSL-T meant to
run in a filesystem, or is it meant to be running on a server and then
doing a HTTP GET on an address that represents a folder of files?

If in the filesystem then what filesystem, and anyway I don't think
there is a way to do it by the file uri scheme definition, however
maybe specific implementations of the file uri scheme would allow you
to give a folder path like file:///c:/ on Windows for example and get
a list of files back. I don't think so though.

Maybe a particular implementation will do this with file uris for you
though? Thus your xsl-t would be processor specific.


Cheers,
Bryan Rasmussen

On Sun, Jun 1, 2008 at 11:05 AM, Dave Pawson <davep@xxxxxxxxxxxxx> wrote:
> I want to generate a list of elements
> which constitutes all the xml files in
> a directory, say ./sub
>
> <reference
>           xmlns:xi='http://www.w3.org/2001/XInclude'>
> <title> Element Reference</title>
> <xi:include href='intro-elements.xml'/>
>
> <xi:include href='sub/a.xml'/>
> <xi:include href='sub/b.xml'/>
> <xi:include href='sub/c.xml'/>
>
> ....
>
>
> </reference>
>
> Any suggestions how this might be done (mostly) with xslt?
> I'm also trying to minimize the OS dependence.
>
>
> TIA
>
> regards
>
> --
> Dave Pawson
> XSLT XSL-FO FAQ.
> http://www.dpawson.co.uk