RE: [xsl] Debug/QC Stylesheets

["Michael Kay" <mike@xxxxxxxxxxxx>]

Try something like this:

<xsl:template match="*">
  <xsl:for-each-group group-adjacent="if (*) then position() else
node-name()">
    <xsl:choose>
      <xsl:when test="current-grouping-key() instance of xs:integer">
        <xsl:value-of select="name()"/>
        <xsl:apply-templates/>
      </xsl:when>
      <xsl:otherwise>
        <xsl:value-of select="count(current-group()), concat(name(),
's'[count(current-group()) ne 1])"/>
      </xsl:otherwise.
    </xsl:choose>

(plus some formatting of course).

The basic idea is to print the names of all the non-leaf elements, and a
summary for a consecutive group of leaf elements with the same name.

Michael Kay
http://www.saxonica.com/


> -----Original Message-----
> From: Nic Gibson [mailto:nicg@xxxxxxxxxx] 
> Sent: 04 June 2008 16:00
> To: xsl-list
> Subject: [xsl] Debug/QC Stylesheets
> 
> Good afternoon
> 
> Quick intro: I'm new here, I'm nic, I abuse and manipulate 
> data (often in XML) for a living, right now I work for Penguin Books.
> 
> I have a debug stylesheet I use to give me a quick overview 
> of xml we get in from data converters. Right now, it dumps 
> out  an html list containing the large scale structure of the 
> xml (it's a DocBook 5
> variant) down to chapter level. Below that level it counts 
> various elements (paras, blockquotes, sections, etc). Our QC 
> people use this script too. This morning, one of them asked 
> me if I could update it so that, rather than outputting 
> something like:
> 
> chapter:
>    24 paragraphs
>    3 sections
>    2 tables
> 
> it could output something like:
> 
>    3 paragraphs
>    1 section
>         2 paragraphs
>    1 table
>    3 paragraphs
> 
> That is it would output the fact that the document contains 3 
> paras then 1 section (which contains 2 paras) then 1 table 
> then 3 more paras.
> 
> Initially, I thought 'dead easy' then I had a bit more of a 
> think and realised that it probably isn't. Right now, I just 
> use something like
> count(descendant::para) get my output. Obviously, that no 
> longer works. Then, I thought that I could probably use 
> following-sibling to get the requested output. Then I 
> realised that it's not that simple either.
> 
> So, the question. Am I wandering down a path that might be 
> easier to traverse using DOM or SAX? If not, can anyone point 
> me in the direction of something similar or suggest an 
> approach? I have a suspicion that I'm missing something obvious.
> 
> cheers
> 
> nic
> --
> Nic Gibson
> Director, Corbas Consulting
> Editorial and Technical Consultancy
> http://www.corbas.co.uk/