RE: [xsl] XQuery basics

Subject: RE: [xsl] XQuery basics
From: "Michael Kay" <mike@xxxxxxxxxxxx>
Date: Wed, 4 Jun 2008 16:57:10 +0100
XQuery is off-topic for this list; try the talk@xxxxxxxxxx list. It's just
as helpful as this list though it has a tiny fraction of the traffic - which
either means that XQuery is much easier to use than XSLT, or that no-one is
using it.

Michael Kay
http://www.saxonica.com/ 

> -----Original Message-----
> From: scarleton@xxxxxxxxx [mailto:scarleton@xxxxxxxxx] On 
> Behalf Of Sam Carleton
> Sent: 04 June 2008 16:43
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: [xsl] XQuery basics
> 
> First off, I am not 100% this is the write place to ask this 
> question, but in years past you all have been very helpful to 
> me with XSLT and thought you might have some insight or know 
> where I should go to get the help I need.
> 
> I have worked with DOM, SAX, XSLT, and XPath in the past and 
> am now working with a framework that has XQuery.  The task at 
> hand is very simple, change (or add if not present) an 
> attribute to one element in an XML document:
> 
> Example: If the name element has an average attribute, change 
> it to 93, otherwise create it and set it to 93
> input:
> 
> <root>
>   <students>
>     <name value="scott"/>
>   </students>
> </root>
> 
> or
> 
> <root>
>   <students>
>     <name value="scott" average="90"/>
>   </students>
> </root>
> 
> output:
> 
> <root>
>   <students>
>     <name value="scott" average="93"/>
>   </students>
> </root>
> 
> Is XQuery like XSLT such that I have to build a little script 
> that will copy everything from the source to the destination 
> and make the change or add the attribute once I get to it?
> 
> Sam

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