Subject: Re: [xsl] Simple XML Diff From: Mark Anderson <mark.anderson@xxxxxxxxxxxxxxxxxxx> Date: Fri, 11 Jul 2008 16:57:17 +0100 |
I'm afraid I can't use extensions either. It has to work with most modern browsers and I have no control over the client environment. So it isn't possible to loop through all elements and attributes in an XML and list all the elements attributes and their path? e.g. <nodeA att1="111"> <nodeA1>AAA</nodeA1> </nodeA> Output: /nodeA = /nodeA/@att1 = 111 /nodeA/nodeA1 = FFF This is the root of my problem, I don't know how to loop thorough everything and get it's absolute path Regards Mark
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