Subject: Re: [xsl] XPath and noname namespace|
From: George Cristian Bina <george@xxxxxxxxxxxxx>
Date: Mon, 14 Jul 2008 18:08:14 +0300
Best Regards, George -- George Cristian Bina <oXygen/> XML Editor, Schema Editor and XSLT Editor/Debugger http://www.oxygenxml.com
I have found workaround but I wonder why it must be done in that way.. Is it some kind of bug in XPath?
I have simple document:<svg xmlns="http://www.w3.org/2000/svg"> <a>aadsf</a> </svg>
And now "//a" doesn't find a node.. I must use //*[local-name() = 'a'], but funny thing is that //*[name() = 'a'] works as well.. Why is that?