Re: [xsl] accessing the input XML's doctype

Subject: Re: [xsl] accessing the input XML's doctype
From: David Carlisle <davidc@xxxxxxxxx>
Date: Wed, 16 Jul 2008 22:44:58 +0100
> But my understanding is that the parser reads in the XML, resolves any
> default attribute values, and then passes the document tree to the XSLT
> processor.  The XSLT processor itself doesn't know or care about the
> doctype information.  Is this correct?

essentially, yes.

what I'd do (if you have write access to local copies of the dtds) is to
ammend them to default a couple of attributes on to th etop level
element which contain the PUBLIC and SYSTEM identifiers.

then if you have

<!DOCTYPE foo PUBLIC "a//b//b" "dtd/this/that'dtd">

If you've modified your local copy of the dtd, the paraser can report

<foo PUBLIC="a//b//b" SYSTEM="dtd/this/that'dtd">

and then picking up the information from xsl is easy.

You then want to use the same ids in output. unfortunately you can't use
dynamically calculated values with doctype-public on xsl:output, but you
can on xsl:result-document, so you just need

<xsl:template match="/">
<xsl:result-document href=".." doctype-public="{*/@PUBLIC)"

If editing the dtd is not an otion for some reason other things can
produce the same effect as defaulting the attribtes yu could (I assume,
not done it personally) interpose a sax filter between the original
source and the xslt engine that just passed everything through except
defaulted these attributes.


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