Re: [xsl] Including an attribute discriminator in the for-each-group's group-by attribute

[Martin Honnen <Martin.Honnen@xxxxxx>]

Mark Wilson wrote:
> I have two elements that differ only by attribute. My for-each-group 
> code currently considers them to be identical, so I need to distinguish 
> them by their attributes as well as their text node. I do not know 
> enough about XPath yet to construct a proper current-grouping-key(). 
> (I'm reading Michael Kay's 4th edition, but have not covered the XPath 
> section yet). Everything I have tried with | @* has failed.
>
> The two elements that need to be distinguished are:
>
> <Heading entry="author">Hahn, Henry</Heading>
> <Heading entry="subject">Hahn, Henry</Heading>
>
> The code snippet is:
>
>      <xsl:for-each-group select="Item" group-by="Heading" 
> collation="{$sorting-collation}">
>        <xsl:sort select="current-grouping-key()" 
> collation="{$sorting-collation}"/>

I am not sure I understand what you want to achieve.
If you want group by the Heading elements which have an attribute 
entry="author" then you can do that with
  <xsl:for-each-group select="Item" group-by="Heading[@entry = 'author']">



--

	Martin Honnen
	http://JavaScript.FAQTs.com/