Re: [xsl] position and loop problem

Subject: Re: [xsl] position and loop problem
From: henry human <henry_human@xxxxxxxx>
Date: Thu, 14 Aug 2008 15:23:54 +0200 (CEST)
Tahnks

>   What do you wanna do exactly?
what i am going to do is, to get the number of the
"section" elements from the XML file, than make a loop
which turns for so many time as the number of the
"section" element existed in the XML file!
I hope i was clear now .



--- Florent Georges <lists@xxxxxxxxxxxx> schrieb:

> henry human wrote:
> 
>   Hi
> 
> > I save the number of a specific node as follow and
> get
> > the right number for the node which is 2:
> >        <xsl:variable name="var"
> >
>
select="count(document/elements/element[@type='section'])"/>
> > However when I try it in a for-each loop as follow
> I
> > get  6 times looping!
> > Hier is the for-each loop:
> 
> > <xsl:for-each select="//*[position() &lt;= $var]">
> 
>   position() doesn't behave as you seem to think it
> does.  What you get
> means there are in the input tree 6 elements that
> are the first or
> second child of their parent element.
> 
>   What do you wanna do exactly?
> 
>   Regards,
> 
> --drkm
> 
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>      
>
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> 
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> 


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