Re: [xsl] Still thinking to object oriented...

["Jonas Bassl" <Jonas@xxxxxxxx>]

yes, i am sorry. That was my mistake, of course, node_b shouldn't
appear in the output. But can you please post your solution as a hole
here, because i don't really know what you mean in the dotted area and
if i try your example like i understood it, than there is a huge
output which is not what i want.

<xsl:template match="/">
:(??)
<xsl:value-of
   select="//*[descendant-or-self::*[contains(name(),'to_search')]]/name()"
   separator="&#10;"/>
</xsl:template>
</xsl:stylesheet>

Regards,
Jonas

2008/9/29 David Carlisle <davidc@xxxxxxxxx>:
>
>> I want to search for all nodes which for this example contain the
>> phrase "to_search" and than i want to ascend from the found node
>> accross the ancestor-or-self axis to output every parent but in the
>> order as they appear in the xml sourc
>
> well that sounds like
>
>
> <xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
>
> <xsl:template match="/">
> :
> <xsl:value-of
>    select="//*[descendant-or-self::*[contains(name(),'to_search')]]/name()"
>    separator="&#10;"/>
> </xsl:template>
> </xsl:stylesheet>
>
>
> but that doesn't produce your requested output, it produces
>
>
> $ saxon9 nodesearch.xml nodesearch.xsl
> <?xml version="1.0" encoding="UTF-8"?>
> :
> node_a
> node_c
> node_d
> node_c
> node_e
> node_c
> node_i
> node_c
> node_l
> node_c
> node_v
> node_d
> node_c
> node_q
> node_c
> node_d
> node_u
> node_c
> node_l
> node_c
> node_d
> node_c
> node_l
> node_c
> node_i
> node_to_search_1
> node_c
> node_s
> node_c
> node_d
> node_c
> node_to_search_2
>
>
>
> you requested node_b but that has no descendant "search" node so I
> don't see why it should be output?
>
>
>
> David
>
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