Subject: [xsl] Using analyze-string to catch roman numerals? From: "Tony Zanella" <tony.zanella@xxxxxxxxx> Date: Thu, 9 Oct 2008 15:18:01 -0400 |
Hello all, Given the following input: <root> <head>CHAPTER II. THE WRECKED FOUNDATIONS OF DOMESTICITY</head> <head>PROBLEMA. HELOISE XXIX.</head> <head>Selected Letters</head> <head>The Second Part of Henry IV.</head> <head>VIII</head> <head>APPENDIX VII</head> <head>Appendix VII</head> <head>APPENDIX</head> <head>CALVIN XVII</head> <head>ILLUSTRATION</head> </root> and the following template: <xsl:template match="head"> <xsl:choose> <xsl:when test="not(matches(.,'^(.*?)([IVXL]+)(.*?)$'))"> <xsl:value-of select="lower-case(.)"/> </xsl:when> <xsl:when test="matches(.,'^(.*?)([IVXL]+)(.*?)$')"> <xsl:analyze-string select="." regex="^(.*?)([IVXL]+)(.*?)$"> <xsl:matching-substring> <xsl:value-of select="lower-case(regex-group(1))"/> <xsl:value-of select="upper-case(regex-group(2))"/> <xsl:value-of select="lower-case(regex-group(3))"/> </xsl:matching-substring> </xsl:analyze-string> </xsl:when> <xsl:otherwise/> </xsl:choose> </xsl:template> I'm trying to use analyze-string to do the following: Test for a roman numeral. If there isn't one, lower-case(.). If there is one, break (.) into its roman numeral and non-roman numeral parts, lower-case()ing the latter. The output I get is: chapter II. the wrecked foundations of domesticity probLema. heloise xxix. selected Letters the second part of henry IV. VIII appendIX vii appendix VII appendIX caLVIn xvii ILLustration When what I want is this: chapter II. the wrecked foundations of domesticity problema. heloise XXIX. selected letters the second part of henry IV. VIII appendix VII appendix VII appendix calvin XVII illustration Between my relative inexperience with both regexes and XSLT, thanks for any help! Tony
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