Subject: Re: [xsl] N input nodes to specific number of ouput nodes From: Colin Paul Adams <colin@xxxxxxxxxxxxxxxxxx> Date: Wed, 22 Oct 2008 18:05:45 +0100 |
>>>>> "Chris" == Bordeman, Chris <Chris.Bordeman@xxxxxxxxxxxxxxxxx> writes: Chris> How? The for-each loop works on the input set which never Chris> gets as high as 10 if there aren't enough items in the Chris> input set. Something like: <xsl:template match="whatever"> <xsl_variable name="length" select="."/> <xsl:choose/> <xsl:when test="count($length) lt 10"> ... <xsl:otherwise> Chris> -----Original Message----- From: Colin Paul Adams Chris> [mailto:colin@xxxxxxxxxxxxxxxxxx] Sent: Wednesday, October Chris> 22, 2008 10:44 AM To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Chris> Subject: Re: [xsl] N input nodes to specific number of Chris> ouput nodes >>>>> "Chris" == Bordeman, Chris <Chris.Bordeman@xxxxxxxxxxxxxxxxx> Chris> writes: Chris> Hi all. Chris> I need to loop through some nodes and output exactly 10 Chris> output nodes, no matter how many input nodes there are. If Chris> too few input nodes the ouput will just show "N/A" and if Chris> too many input nodes they will just be ignored. Chris> I can do the 'too many' with a for-each and a choose based Chris> on position() but don't get how the 'too few' scenario is Chris> handled. Chris> An xsl:choose discriminating on count() should do the Chris> trick. -- Colin Adams Preston Lancashire -- Colin Adams Preston Lancashire
Current Thread |
---|
|
<- Previous | Index | Next -> |
---|---|---|
Re: [xsl] N input nodes to specific, Martin Honnen | Thread | RE: [xsl] N input nodes to specific, Michael Kay |
Re: [xsl] N input nodes to specific, Andrew Welch | Date | Re: [xsl] N input nodes to specific, Martin Honnen |
Month |