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Subject: [xsl] my node position within a certain context, efficiently? From: Syd Bauman <Syd_Bauman@xxxxxxxxx> Date: Sat, 25 Oct 2008 00:13:48 -0400 |
I sorta suspect that if I knew what to look for, I could find this in
the archives or Dave Pawson's FAQ, but I haven't so far.
My input documents will look something like this:
<stuff>
<thing>zero</thing>
<box>
<thing>one</thing>
<thing>two</thing>
<list>
<item>
<thing>three</thing>
</item>
<item>
<thing>four</thing>
</item>
</list>
<note>
<thing>five</thing>
<thing>six</thing>
</note>
<thing>seven</thing>
<thing>eight</thing>
</box>
<thing>nine</thing>
<thing>ten</thing>
</stuff>
That is, there are <thing>s both inside and outside of <box>es, and
those that are inside a <box> may be children or descendants at
almost any depth.
For each <thing> that is inside a <box> I want its position within
the box. I.e., for the above input, I'd like to be able to generate
the following output from within a template that has matched <thing>s
inside <box>es.
<thing myCount="1">one</thing>
<thing myCount="2">two</thing>
<thing myCount="3">three</thing>
<thing myCount="4">four</thing>
<thing myCount="5">five</thing>
<thing myCount="6">six</thing>
<thing myCount="7">seven</thing>
<thing myCount="8">eight</thing>
I pretty quickly came up with a way to do this. It would even work in
XSLT 1.0, although this particular stylesheet is in 2.0. But I am
wondering if there isn't a better way. Does this work for all such
cases, or have I missed something? Is this insanely inefficient?
<xsl:template match="box//thing">
<xsl:copy>
<xsl:attribute name="myCount">
<xsl:value-of select="1 + count(preceding::thing) - count(ancestor::box/preceding::thing)"/>
</xsl:attribute>
<xsl:apply-templates/>
</xsl:copy>
</xsl:template>
Thanks.
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