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Subject: RE: [xsl] xsl:sort with nulls at end From: "Michael Kay" <mike@xxxxxxxxxxxx> Date: Mon, 3 Nov 2008 18:19:03 -0000  | 
> The issue I have is that if the row is missing that tag, the 
> sort puts that record first. Ie. Nulls come first. I need the 
> nulls to come last.
> Is there a way to get around this and force the nulls to be last?
Add further sort keys:
      <xsl:for-each select="*">
          <xsl:sort select="empty(X)"/>
          <xsl:sort select="X" order="ascending" data-type="text"/>
          <xsl:sort select="empty(Y)"/>
          <xsl:sort select="Y" order="descending" data-type="text"/>
          <xsl:sort select="empty(Z)"/>
          <xsl:sort select="Z" order="ascending" data-type="number"/>
Note that boolean false() sorts before true().
Michael Kay
http://www.saxonica.com/
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