RE: [xsl] How the other half live

Subject: RE: [xsl] How the other half live
From: "Michael Kay" <mike@xxxxxxxxxxxx>
Date: Tue, 18 Nov 2008 15:21:43 -0000
> for $d in distinct-values($seq) return $d[count($seq[. eq $d]) ge $i]
> equivalent?  I think it is, and probably a lot more 
> efficient, although it is longer.

They are both O(n^2).

What about:

<xsl:for-each-group select="$seq" group-by=".">
  <xsl:sequence select="current-group()[$i]"/.

which also scores quite well on brevity, I think - in syntax tree form, it
has 6 nodes which is the same as Dimitre's expression; and I think it rates
higher on both efficiency and clarity.

Michael Kay

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