Re: [xsl] Random selection

Subject: Re: [xsl] Random selection
From: sudheshna iyer <sudheshnaiyer@xxxxxxxxx>
Date: Sun, 30 Nov 2008 10:08:02 -0800 (PST)
Thank you very much Mukul. This is exactly what I am looking for.

One more question.

1. How do you do xsl transformation. When I tried to do xsl transformation using the following xsl and xml from xml spy, I am receiving the following error.

This file is not valid.
Error in xpath expression. Function not found in namespace..

2. When I tried to transformation using java:

  ByteArrayOutputStream baos = new ByteArrayOutputStream();
    SAXTransformerFactory saxTFactory = ((SAXTransformerFactory) tf);
    tHandler1 = saxTFactory.newTransformerHandler(new StreamSource(xsllocation)); --> Missing or incorrect XSLT Namespace.
    Transformer tr1 = tHandler1.getTransformer();
    xsllocation --> this is the location of xsl file in your local directory.

What is the way that you recomment?

Thanks again for your help

--- On Sun, 11/30/08, Mukul Gandhi <gandhi.mukul@xxxxxxxxx> wrote:
From: Mukul Gandhi <gandhi.mukul@xxxxxxxxx>
Subject: Re: [xsl] Random selection
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Date: Sunday, November 30, 2008, 12:52 PM

Hi Dimitre,
  I would prefer a portable solution if it's really required (i.e., my
IT architecture demands it).

If I know my stylesheet will always run in a Java environment, what's
the harm in using the Java extensions provided by the processor?

On Sun, Nov 30, 2008 at 10:32 PM, Dimitre Novatchev
<dnovatchev@xxxxxxxxx> wrote:
> Hi Mukul,
> What about people, who use C#, Python, VB, C++, ..., etc?
> I strongly believe that recommending a non-portable solution on this
> list when a known, 100% XSLT, portable one exists, should be
> discouraged.
> --
> Cheers,
> Dimitre Novatchev

Mukul Gandhi

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