Subject: Re: [xsl] Random selection From: sudheshna iyer <sudheshnaiyer@xxxxxxxxx> Date: Sun, 30 Nov 2008 10:08:02 -0800 (PST) |
Thank you very much Mukul. This is exactly what I am looking for. One more question. 1. How do you do xsl transformation. When I tried to do xsl transformation using the following xsl and xml from xml spy, I am receiving the following error. This file is not valid. Error in xpath expression. Function not found in namespace.. 2. When I tried to transformation using java: ByteArrayOutputStream baos = new ByteArrayOutputStream(); SAXTransformerFactory saxTFactory = ((SAXTransformerFactory) tf); tHandler1 = saxTFactory.newTransformerHandler(new StreamSource(xsllocation)); --> Missing or incorrect XSLT Namespace. Transformer tr1 = tHandler1.getTransformer(); xsllocation --> this is the location of xsl file in your local directory. What is the way that you recomment? Thanks again for your help --- On Sun, 11/30/08, Mukul Gandhi <gandhi.mukul@xxxxxxxxx> wrote: From: Mukul Gandhi <gandhi.mukul@xxxxxxxxx> Subject: Re: [xsl] Random selection To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Date: Sunday, November 30, 2008, 12:52 PM Hi Dimitre, I would prefer a portable solution if it's really required (i.e., my IT architecture demands it). If I know my stylesheet will always run in a Java environment, what's the harm in using the Java extensions provided by the processor? On Sun, Nov 30, 2008 at 10:32 PM, Dimitre Novatchev <dnovatchev@xxxxxxxxx> wrote: > Hi Mukul, > > What about people, who use C#, Python, VB, C++, ..., etc? > > I strongly believe that recommending a non-portable solution on this > list when a known, 100% XSLT, portable one exists, should be > discouraged. > > > -- > Cheers, > Dimitre Novatchev -- Regards, Mukul Gandhi
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