Re: [xsl] sequence of strings

Subject: Re: [xsl] sequence of strings
From: Ruud Grosmann <r.grosmann@xxxxxx>
Date: Tue, 02 Dec 2008 15:25:15 +0100
Florent Georges wrote:
Ruud Grosmann wrote:

Dag Ruud,

My question is: this solution looks clumsy. How can I improve it?

I don't have the time to analyze your stylesheet, but a few remarks... It seems you use a string to represent structured values. Why don't you use something structured? In XSLT 2.0, you can pass a sequence of strings like this:

The string is more or less my input. My input is an upcast output document.

<xsl:with-param name="style" select="'italic', 'bold'"/>

  Unfortunately, you can't have nested sequences, so you can't have
something like, say:

    <!-- Do not try this at home! -->
    <xsl:with-param name="values" select="
        ('style', ('italic', 'bold')),
        ('key',   ('val1', 'val2', ...))"/>

But you can use several parameters if suitable:

    <xsl:with-param name="style" select="'italic', 'bold'"/>
    <xsl:with-param name="key"   select="'val1', 'val2', ..."/>

Or you can always use XML:

    <xsl:with-param name="values">

  Instead of contains(), you will then be able to use regular XPath
set operators and mapping techniques:

    <xsl:template name="get_attributes" as="xs:string?">
       <xsl:param name="style" as="xs:string*"/>
       <xsl:variable name="map">
          <i key="bold"   name="BLD"/>
          <i key="italic" name="ITA"/>
       <xsl:sequence select="$map/i[@key = $style][1]/@name"/>

Yes, Michael had this solution too. I am very glad you made we aware of this possibility.

And if you use a function instead of a named template, you can use the following to get the element name (but that's really a matter of taste):

my:get-element-name(('bold', 'italic'))


Thanks for your help too, Florent.

regards, Ruud

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