Subject: Re: [xsl] sequence of strings From: Ruud Grosmann <r.grosmann@xxxxxx> Date: Tue, 02 Dec 2008 15:25:15 +0100 |
Ruud Grosmann wrote:
Dag Ruud,
My question is: this solution looks clumsy. How can I improve it?
I don't have the time to analyze your stylesheet, but a few remarks... It seems you use a string to represent structured values. Why don't you use something structured? In XSLT 2.0, you can pass a sequence of strings like this:
<xsl:with-param name="style" select="'italic', 'bold'"/>
Unfortunately, you can't have nested sequences, so you can't have something like, say:
<!-- Do not try this at home! --> <xsl:with-param name="values" select=" ('style', ('italic', 'bold')), ('key', ('val1', 'val2', ...))"/>
But you can use several parameters if suitable:
<xsl:with-param name="style" select="'italic', 'bold'"/> <xsl:with-param name="key" select="'val1', 'val2', ..."/>
Or you can always use XML:
<xsl:with-param name="values"> <style> <italic/> <bold/> </style> <key> <val1/> <val2/> ... </key> </xsl:with-param>
Instead of contains(), you will then be able to use regular XPath set operators and mapping techniques:
<xsl:template name="get_attributes" as="xs:string?"> <xsl:param name="style" as="xs:string*"/> <xsl:variable name="map"> <i key="bold" name="BLD"/> <i key="italic" name="ITA"/> </xsl:variable> <xsl:sequence select="$map/i[@key = $style][1]/@name"/> </xsl:template>
And if you use a function instead of a named template, you can use the following to get the element name (but that's really a matter of taste):
my:get-element-name(('bold', 'italic'))
Regards,
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