|
Subject: [xsl] How to sort a $variable and store that into another $variable ? From: "Jean-Philippe Martin" <jeanph01@xxxxxxxxx> Date: Wed, 10 Dec 2008 13:15:04 -0500 |
Hi,
I'm trying to sort a <xsl:variable> containing 22 nodes and store this
sorted list into another xsl:variable.
Is this possible ?
Here's the best I could do :
<xsl:variable name="sortedList">
<xsl:call-template name="sortThis">
<xsl:with-param name="unsortedList" select="$unsortedList"/>
</xsl:call-template>
</xsl:variable>
<xsl:template name="sortThis">
<xsl:param name="unsortedList"/>
<xsl:for-each select="$unsortedList">
<xsl:sort select="."/>
<xsl:copy-of select="."/>
</xsl:for-each>
</xsl:template>
I have also tried it this way but with the same result :
<xsl:variable name="sortedList">
<xsl:apply-templates mode="sort" select="$unsortedList">
<xsl:sort select="."/>
</xsl:apply-templates>
</xsl:variable>
<xsl:template match="node()" mode="sort">
<xsl:copy-of select="@*"/>
</xsl:template>
What I get is a single node containing all the values sorted
concatenated in a single string.
Is there a way to do this ?
Ps: this is xsl 1.0.
Thank you very much.
| Current Thread |
|---|
|
| <- Previous | Index | Next -> |
|---|---|---|
| [xsl] [ANN] XML Prague 2009 Registr, Jim Fuller | Thread | Re: [xsl] How to sort a $variable a, Martin Honnen |
| Re: [xsl] Generating ID key values, Vasu Chakkera | Date | Re: [xsl] How to sort a $variable a, Martin Honnen |
| Month |