Re: [xsl] removing trailing space for all the elements

Subject: Re: [xsl] removing trailing space for all the elements
From: George Cristian Bina <george@xxxxxxxxxxxxx>
Date: Thu, 11 Dec 2008 12:07:56 +0200
Hi,

Something like below will do it:

<xsl:template match="node() | @*">
    <xsl:copy>
        <xsl:apply-templates select="node() | @*"/>
    </xsl:copy>
</xsl:template>

<xsl:template match="text()" priority="1">
<xsl:variable name="normalized" select="normalize-space(.)"/>
<xsl:variable name="firstToken" select="substring-before($normalized, ' ')"/>
<xsl:value-of select="if ($normalized='' or $firstToken!='')
then concat ($firstToken, substring-after(., $firstToken))
else concat ($normalized, substring-after(., $normalized))
"/>
</xsl:template>


Depending on your actual needs you may find that the simpler solution below also works for you:

<xsl:template match="node() | @*">
    <xsl:copy>
        <xsl:apply-templates select="node() | @*"/>
    </xsl:copy>
</xsl:template>

<xsl:template match="text()" priority="1">
    <xsl:value-of select="normalize-space(.)"/>
</xsl:template>

Best Regards,
George
--
George Cristian Bina
<oXygen/> XML Editor, Schema Editor and XSLT Editor/Debugger
http://www.oxygenxml.com

M Balaji wrote:
Hi All,

 I need to remove trailing space for all the elements. Any help
appreciated.

Input:

 <?xml version="1.0"?>
 <Toc>
 <a> Say you want display this <emph type="b"> data</emph> in the form of a
 sequentially numbered booklist.</a>
 </Toc>

Expected Output:

 <?xml version="1.0"?>
<Toc>
<a>Say you want display this <emph type="b">data</emph> in the form of a
sequentially numbered booklist.</a>
</Toc>


Tried Coding:


<xsl:stylesheet xmlns:xsl=http://www.w3.org/1999/XSL/Transform version="1.0">

<xsl:template match="*|@*">
<xsl:copy>
<xsl:apply-templates select="normalize-space(*)"/>
</xsl:copy>
</xsl:template>

</xsl:stylesheet>


For the above style sheet I'm getting error "apply-templates expected node()" and I'm using saxon version 8.


Thanks in advance, Balaji. M

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