Re: [xsl] flattening an xml hierarchy

Subject: Re: [xsl] flattening an xml hierarchy
From: "Vasu Chakkera" <vasucv@xxxxxxxxx>
Date: Fri, 9 Jan 2009 10:30:35 +0000
>>You probably don't want to process attributes of the unwanted elements.
>> With your code below, an attribute on <Dontwant1> would cause a run-time
>> error.

True..



2009/1/9 Vasu Chakkera <vasucv@xxxxxxxxx>:
> On 08/01/2009, Evan Lenz <evan@xxxxxxxxxxxx> wrote:
>> You probably don't want to process attributes of the unwanted elements.
>> With your code below, an attribute on <Dontwant1> would cause a run-time
>> error.
>>
>> Evan
>>
>> Vasu Chakkera wrote:
>>> USe identity transformation.
>>>
>>> <xsl:stylesheet version="1.0"
>>> xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
>>>      <xsl:template match="node()|@*">
>>>              <xsl:copy>
>>>                      <xsl:apply-templates select="node()|@*"/>
>>>              </xsl:copy>
>>>      </xsl:template>
>>>      <xsl:template match = "Dontwant1">
>>>              <xsl:apply-templates select="node()|@*"/>
>>>      </xsl:template>
>>>      <xsl:template match = "dontwant2"/>
>>> </xsl:stylesheet>
>>>
>>> This will do your job. Although.. You have 2 definitions of what you
>>> want to Remove.
>>>
>>> 1. Node and its children
>>> 2. Node .
>>>
>>> I am not sure what you meant by "remove" But anyway, in either case,
>>> if you want to remove node and all its children, you just define an
>>> empty template
>>> if you want to ignore the node alone, then you define the template for
>>> that node and not bothor about copying the current node, and copy all
>>> its children.
>>>
>>> HTH
>>>
>>> 2009/1/8 Tim <timlhunt@xxxxxxxxxxxxxx>:
>>>
>>>> Hi,
>>>> I'd like to remove some elements from an xml hierachy using xslt:
>>>>
>>>> Original xml example:
>>>> <Dontwant1>
>>>>   <dontwant2>foo</dontwant2>
>>>>   <x3>
>>>>       <x4>stuff</x4>
>>>>       <y5>more stuff</y5>
>>>>   </x3>
>>>> </Dontwant1>
>>>>
>>>> Like to have transform output:
>>>> <x3>
>>>>  <x4>stuff</x4>
>>>>   <y5>more stuff</y5>
>>>> </x3>
>>>>
>>>> Thanks for your insghts.
>>>>
>>>> Tim
>>
>>
>
>
> --
> Vasu Chakkera
> Numerical Algorithms Group Ltd.
> Oxford
> www.vasucv.com
>



-- 
Vasu Chakkera
Numerical Algorithms Group Ltd.
Oxford
www.vasucv.com

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