Re: [xsl] read directory and get it as an array

["Joe Fawcett" <joefawcett@xxxxxxxxxxx>]

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From: "J. S. Rawat" <jrawat@xxxxxxxxxxxxxx>
Sent: Friday, January 16, 2009 10:00 AM
To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx>; <xsl-list@xxxxxxxxxxxxxxxxxxxxxx>
Subject: Re: [xsl] read directory and get it as an array

> At 12:20 PM 1/16/2009, Mukul Gandhi wrote:
> > The variable 'file-collection' will contain a sequence of nodes
>
> But I need names of the files within a directory.
>
> ABC
>    a.xml
>    b.xml
> I want to a.xml and b.xml should be hold as an array. Below is perl code 
> for doing the same.
>
> opendir (DIR, "ABC");
> while($filename = readdir(DIR))
> {
>         push (@filearray, $filename);
> }
> closedir(DIR);
>         for ($i=3; $i<=$#filearray; $i++)
>         {
>           open(INFILE, "<ABC/$filearray[$i]");
But XML/XSLT doesn't have 'arrays'. So if you want to deal with a collection 
of files from within XSLT you can use 'collection,' if you want to deal with 
them in a another language then use that language's constructs. I don't see 
where collection lets you down given an XSLT scenario.

Joe

http://joe.fawcett.name