Subject: Re: [xsl] read directory and get it as an array From: "Joe Fawcett" <joefawcett@xxxxxxxxxxx> Date: Fri, 16 Jan 2009 10:06:27 -0000 |
-------------------------------------------------- From: "J. S. Rawat" <jrawat@xxxxxxxxxxxxxx> Sent: Friday, January 16, 2009 10:00 AM To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx>; <xsl-list@xxxxxxxxxxxxxxxxxxxxxx> Subject: Re: [xsl] read directory and get it as an array
At 12:20 PM 1/16/2009, Mukul Gandhi wrote:But XML/XSLT doesn't have 'arrays'. So if you want to deal with a collection of files from within XSLT you can use 'collection,' if you want to deal with them in a another language then use that language's constructs. I don't see where collection lets you down given an XSLT scenario.The variable 'file-collection' will contain a sequence of nodes
But I need names of the files within a directory.
ABC
a.xml
b.xml
I want to a.xml and b.xml should be hold as an array. Below is perl code for doing the same.
opendir (DIR, "ABC"); while($filename = readdir(DIR)) { push (@filearray, $filename); } closedir(DIR); for ($i=3; $i<=$#filearray; $i++) { open(INFILE, "<ABC/$filearray[$i]");
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