Subject: Re: [xsl] Using XSLT to change XML and modify node with XPath From: kheris <kheris@xxxxx> Date: Thu, 05 Feb 2009 20:50:39 +0100 |
Hi all, Maybe anyone can still help me on this: I need to transform XML1 to XML2. The procedure i am looking for is something like: 1) i reach the node var-path 2) i meet the node path. I get the value, and i search for /def[name=value] 3) i meet the second node path in current var-path. I get the value, and now i search for /def[name=value_of_path_before]//def[value_of_path_now] 4) etc. So, i use previously found node as starting node now. What is more, i need to use //, as structure of path can be deeper then explicitly said. But i can return only first found node (so, if more nodes satisfy that, i get always the first one). I have XQuery for searching/modifying nodes. Maybe is it possible to combine it (i tried to google some more info, but most tool don't allow that) XML 1: <?xml version="1.0" encoding="UTF-8"?> <xml> <def> <name>Var1</name> <val>0</val> <def> <name>SubVar</name> <val>012</val> </def> </def> <def> <name>Var2</name> <val>1</val> </def> <test-node> <use> <var-path> <path>Var1</path> <path>SubVar</path> </var-path> </use> </test-node> </xml> XML 2: <?xml version="1.0" encoding="UTF-8"?> <xml> <def> <name>Var1</name> <val>0</val> <def> <name>SubVar</name> <val>012</val> </def> </def> <def> <name>Var2</name> <val>1</val> </def> <test-node> <use> <var-path> <path value="0">Var1</path> <path value="012">SubVar</path> </var-path> </use> </test-node> </xml>
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