Subject: Re: [xsl] [XML namespaces] From: Pedro Henrique Marques <pedrohml@xxxxxxxxx> Date: Tue, 24 Mar 2009 02:19:51 -0300 |
I did'nt acquire the desirable output. The xslt ommits the tag <dc:source> in the process: My xslt file (spinner2dml.xsl): <?xml version="1.0" encoding="ISO-8859-1"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"; xmlns:dc="http://url.com"> <xsl:output method="xml"/> <xsl:template match="catalog"> <xsl:for-each select="item"> <Document> <xsl:for-each select="category"> <Category><xsl:value-of select="."/></Category> </xsl:for-each> <xsl:copy-of select="dc:source"/> </Document> </xsl:for-each> </xsl:template> </xsl:stylesheet> My XML file: <?xml version="1.0" encoding="ISO-8859-1"?> <?xml-stylesheet type="text/xsl" href="spinner2dml.xsl"?> <catalog xmlns:dc="http://www.w3.org/"> <item> <title>~*Rainbow Guidance*~</title> <link>http://blog.myspace.com/index.cfm?fuseaction=blog.view&friendID=13345245&blogID=420014399</link> <guid>http://blog.myspace.com/index.cfm?fuseaction=blog.view&friendID=13345245&blogID=420014399</guid> <pubDate>Fri, 01 Aug 2008 00:04:38 GMT</pubDate> <dc:source>http://blog.myspace.com/kristindunngalbraith</dc:source> <category>Dreams and the Supernatural</category> </item> </catalog> My (processor) output: (xsltproc) "<Document><Category>Dreams and the Supernatural</Category></Document>" (saxon) "<?xml version="1.0" encoding="utf-8"?><Document xmlns:dc="http://url.com"><Category>Dreams and the Supernatural</Category></Document>" (xalan) "<?xml version="1.0" encoding="utf-8"?><Document xmlns:dc="http://url.com"><Category>Dreams and the Supernatural</Category></Document>" I need to get the value of <dc:source>. What can I do for it ?
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