Subject: Re: [xsl] copy attribute question From: Garvin Riensche <g.riensche@xxxxxxx> Date: Wed, 25 Mar 2009 00:06:02 +0100 |
There is none. So the default apply-templates is used which doesn't select template 1 because it matches an attribute node.If template 1 doesn't produce any output that's because it's not being invoked. Where is the apply-templates call that selects a node that it would match?
regards, Garvin
Michael Kay
http://www.saxonica.com/
-----Original Message-----
From: Garvin Riensche [mailto:g.riensche@xxxxxxx] Sent: 24 March 2009 22:14
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: [xsl] copy attribute question
Hello,
I am wondering why the context seems to be different in the following templates because I thought the output would be the same.
Input: <a id="1"/>
Template 1: <xsl:template match="a/@*"> <aa> <xsl:copy/> </aa> </xsl:template>
Template 2: <xsl:template match="a"> <xsl:for-each select="@*"> <aa> <xsl:copy/> </aa> </xsl:for-each> </xsl:template>
Template 1 doesn't produce any output and template 2 outputs: <aa id="1"/>
Why doesn't Template 1 copy the attribute node to element <aa> like template 2?
regards, Garvin
Current Thread |
---|
|
<- Previous | Index | Next -> |
---|---|---|
RE: [xsl] copy attribute question, Michael Kay | Thread | [xsl] XSLT in MSXML - removeParamet, Scott Trenda |
RE: [xsl] Compound filter in for-ea, Michael Kay | Date | [xsl] XSLT in MSXML - removeParamet, Scott Trenda |
Month |