Re: [xsl] Problem with <xsl:if>

Subject: Re: [xsl] Problem with <xsl:if>
From: Martin Honnen <Martin.Honnen@xxxxxx>
Date: Sun, 05 Apr 2009 13:01:04 +0200
Pierluigi Fabbris wrote:

                <xsl:if test="./ricetta/@id =vino_consigliato/@ricetta">
                               <xsl:value-of
select="/ricettario/vino_consigliato/@text()"/>
                </xsl:if>

I think instead of the xsl:if and xsl:value-of you simply want
<xsl:value-of
select="/ricettario/vino_consigliato[@ricetta = current()/@id]"/>
That would output the string value of that "vino_consigliato" element for which the "ricetta" attribute is equal to the "id" attribute of the current "ricetta" element.


--

	Martin Honnen
	http://JavaScript.FAQTs.com/

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