Re: [xsl] Can this all fit into one Xpath expression?

["G. Ken Holman" <gkholman@xxxxxxxxxxxxxxxxxxxx>]

At 2009-04-14 14:02 -0500, russurquhart1@xxxxxxxxxxx wrote:
> I have a structure with conditions something like this:
>
> //GenTable/table/tgroup/tbody/row/entry[Emphasis = 'Address Offset'] 
> and Emphasis[@type='bold']
>
> //GenTable/table/tgroup/tbody/row/entry[Emphasis = 'Physical 
> Address'] and Emphasis[@type='bold']
>
> //GenTable/table/tgroup/tbody/row/entry[Emphasis = 'Instance'] and 
> Emphasis[@type='bold']
>
> //GenTable/table/tgroup/tbody/row/entry[Emphasis = 'Description'] 
> and Emphasis[@type='bold']
>
> //GenTable/table/tgroup/tbody/row/entry[Emphasis = 'Type'] and 
> Emphasis[@type='bold']
>
> If a GenTable element has four or the five entry elements, that 
> match these conditions, i want to set GenTable[@role='Register'] and 
> GenTable[@columns='1'].
>
> Can this be squeezed into one hairy Xpath expression.

In XPath 2.0 you can use sequence notation and have:

//GenTable/table/tgroup/tbody/row/entry[Emphasis[ . = ( 'Address Offset',
                                                        'Physical Address',
                                                        'Instance',
                                                        'Description',
                                                        'Type' ) ]
                                                [@type='bold']
                                       ]

That would select the entry element that has the emphasis you seek 
... then in XSLT or XQuery you construct the end result by 
constructing the element and attribute nodes you need.  It doesn't 
handle nested emphasis, only emphasis that is a direct child of the 
entry.  If you need to identify an entry with emphasis anywhere 
inside of it you need to modify the above to read:

  ... entry[.//Emphasis[ ....

I'm not sure to what you are referring when you say "I want to set 
...." ... are you using XPath in, perhaps, a DOM implementation?

I hope this helps.

. . . . . . . . . Ken

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