Subject: RE: [xsl] Big long xpath, almost there, but not quite From: "Michael Kay" <mike@xxxxxxxxxxxx> Date: Thu, 16 Apr 2009 19:20:59 +0100 |
Your expression is count (A or B or C or D or E) >= 4 But (A or B or C or D or E) is a boolean, and the count() of a single boolean value is always 1. Try count((boolean(A), boolean(B), boolean(C), boolean(D), boolean(E))[.]) >= 4 The unusual predicate [.] selects those booleans in the sequence that are true. Michael Kay http://www.saxonica.com/ > -----Original Message----- > From: russurquhart1@xxxxxxxxxxx [mailto:russurquhart1@xxxxxxxxxxx] > Sent: 16 April 2009 19:03 > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > Subject: [xsl] Big long xpath, almost there, but not quite > > > > I want to thank everybody for their help on this. Michael > Kay, thaks for your help very much. I entered the following > Xpath. It is getting there, but it still is not quite right. > > //GenTable[count(entry[Emphasis[normalize-space(.) = 'Address > Offset' and @type='bold'] or > Emphasis[normalize-space(.)='Physical Address' and > @type='bold'] or Emphasis[normalize-space(.)='Instance' and > @type='bold'] or Emphasis[normalize-space(.)='Description' > and @type='bold'] or Emphasis[normalize-space(.)='Type' and > @type='bold'] ]) >= 4] > > When i use this, as i would like at least 4 entry element > that match the conditions above, hopefully 5, i would think > this should do the trick and return the GenTable elements > that contain them. > > When i run it, however, i get no GenTable elements. When i > remove the count() function, i get no GenTable elements. When > i change the 4 9the minimum match value, to something smaller > like 1) i get no GenTable elements. When i change the number > 4 to 0, i get ALL the GenTable elements. > > I would have thought that removing the count() function would > have given me all the GenTable elements containing those > entry elements. > > Could someone explain a little about this? The reasoning > seems sound, i just don't know why it is doing what it is! > > thanks again, > > > Russ
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