Subject: Re: [xsl] conditional multiple outputs From: Michael Müller-Hillebrand <mmh@xxxxxxxxxxxxx> Date: Thu, 14 May 2009 12:52:37 +0200 |
You basically loop through all <title> in document order and try to create a new document for each <title>. So the second time you see a title with "file 1" your XSL tries to create another file1.xml - boom!
<xsl:result-document href="file1.xml"> <xsl:for-each select="title[starts-with(., 'file 1')]"> <xsl:copy-of select="."/> </ </ <xsl:result-document href="file2.xml"> <xsl:for-each select="title[starts-with(., 'file 2')]"> <xsl:copy-of select="."/> </ </ <xsl:result-document href="file3.xml"> <xsl:for-each select="title[starts-with(., 'file 3')]"> <xsl:copy-of select="."/> </ </
Hi,
I am trying to generate multiple output files in a single template (see xsl file below). The scenario is the following:
1. I read elements <title> one after the other from a input file "content.xml" 2. if the text of the element <title> begins with the substring "file 1", then copy the element to the output file file1.xml, if it begins with "file 2" then output to file2.xml, else copy the element to file3.xml.
The processor I use is Saxon B on .NET and XLST version is 2.0. But my script does not work since I always have following error message:
E:\test\xsl>Transform -s:"e:\test\xsl\content.xml" -xsl:"e:\test\xsl\import.xsl Error at xsl:choose on line 8 of file:///e:/test/xsl/import.xsl: XTDE1490: Cannot write more than one result document to the same URI, or write to a URI that has been read: file:/E:/test/xsl/file2.xml Transformation failed: Run-time errors were reported
Here are the script and the input file content.xml:
<!--content.xml--> <?xml version="1.0" encoding="UTF-8"?> <groups> <group> <title>file 1 xxx </title> <title>file 2 efg </title> </group> <group> <title>file 2 xxx </title> <title>file 3 abc </title> </group> <group> <title>file 1 abc </title> <title>file 3 xyz </title> </group> <group> <title>file 2 zzz </title> <title>file 2 ihk </title> </group> </groups>
<!--multipleOutput.xsl--> <?xml version="1.0"?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="2.0"> <xsl:output method="xml" indent="yes" encoding="utf-8"/> <xsl:template name="test" match="/"> <xsl:for-each select="groups/group"> <xsl:for-each select="title"> <xsl:variable name="textOfTheElementTitle" select="substring(./text(), 1, 6)"/> <xsl:choose> <xsl:when test="matches($textOfTheElementTitle, 'file 1', 'i')"> <xsl:result-document href="file1.xml">
<contentOfTitleElmt>
<xsl:value-of select="./text()"/> </ contentOfTitleElmt> </xsl:result-document> </xsl:when> <xsl:when test="matches($textOfTheElementTitle, 'file 2', 'i')"> <xsl:result-document href="file2.xml">
<contentOfTitleElmt>
<xsl:value-of select="./text()"/> </ contentOfTitleElmt> </xsl:result-document> </xsl:when> <xsl:otherwise> <xsl:result-document href="file3.xml">
<contentOfTitleElmt>
<xsl:value-of select="./text()"/> </ contentOfTitleElmt> </xsl:result-document> </xsl:otherwise> </xsl:choose> </xsl:for-each> </xsl:for-each> </xsl:template> </xsl:stylesheet>
Does somebody know why it does not work? Should I use another function than xsl:result-document?
Many thanks in advance, Regards
Horace
-- _______________________________________________________________ Michael M|ller-Hillebrand: Dokumentations-Technologie Adobe Certified Expert, FrameMaker Lvsungen und Training, FrameScript, XML/XSL, Unicode Blog: http://cap-studio.de/ - Tel. +49 (9131) 28747
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