Re: [xsl] Re: Determining whether no single instance of a specific node exists

[Michael Dykman <mdykman@xxxxxxxxx>]

On Thu, Jun 4, 2009 at 2:27 PM, Mark Peters <markpeters.work@xxxxxxxxx>
wrote:
> Sorry, my XSL examples weren't quite right.  I'm trying to determine
> whether no instance of <c/> exists for each <b/> set.
>
> So, in my XSL document, assume I'm processing each <a/> node.
>
> 1,
> <xsl:when test="not(b/c)">
>
> 2.
> <xsl:when test="count(not(b/c)) &gt;= 1">
>
> Thanks,
> Mark
>
>
> On Thu, Jun 4, 2009 at 2:20 PM, Mark Peters <markpeters.work@xxxxxxxxx>
wrote:
>> Hi Everyone,
>>
>> I have the following XML document:
>>
>>     <a>
>>             <b/>
>>             <b/>
>>             <b/>
>>     </a>
>>     <a>
>>             <b/>
>>             <b/>
>>             <b>
>>                     <c/>
>>             </b>
>>
>>     </a>
>>     <a>
>>             <b/>
>>             <b/>
>>             <b/>
>>     </a>
>>
>> For each <b/> set, I want to apply a transformation only if no single
>> instance of <c/> exists. I know how to check whether a node does
>> exist, but not how to check whether no single instance of the node
>> exists.
>>
>> I've tried the following conditional statements without success:
>>
>> 1,
>> <xsl:when test="not(a/b/c)">
>>
>> 2.
>> <xsl:when test="count(not(a/b/c)) &gt;= 1">
>>
>>
>> What conditional statement should I use?
>>
>> Thanks in advance for any help.
>>

Are you looking for something along the line of

<xsl:when test="not(count(b/c) &gt;= 1)">
??
--
 - michael dykman
 - mdykman@xxxxxxxxx

 - All models are wrong.  Some models are useful.