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Subject: Re: [xsl] Joining xml documents on the fly From: Lars Huttar <lars_huttar@xxxxxxx> Date: Mon, 08 Jun 2009 09:56:32 -0500 |
On 6/8/2009 9:43 AM, Joelle Tegwen wrote:
> Ok, now I've got a new twist on the same type of data set.
>
> Now I want to find all of the people in <project_staff_roles> who are
> listed more than, arbitrarily, 5 times.
>
> I get somewhere around this:
> <xsl:variable name="common"
>
> select="$project_staff_roles/project_staff_role/@staff_id[count($project_staff_roles/project_staff_roles/@staff_id
> = .) > $common_count]"/> and of course this doesn't work.
If you change
project_staff_roles/@staff_id
to
project_staff_role/@staff_id
(remove the extra 's') does it work? Seems like it should.
Of course that will give you a nodeset of staff id's, and each one in
the set will be repeated at least $common_count + 1 times, and the
repeats for different people will be mixed.
If you're using XSLT 2.0 you could do something like
for-each-group select="project_staff_roles/project_staff_role"
group-by="@staff_id"
if test="count(current-group()) > $common_count"
value-of select="current-group()[1]/@staff_id"
That would give you each staff_id only once.
Lars
>
> I'm sorry, I'm just really struggling with the underlying concepts here.
> I think I'm trying to approach this from an SQL point of view and I'm
> just not able to re-frame my thought process correctly.
>
> Thanks much again.
> Joelle
>
> Joelle Tegwen wrote:
>> Ok, I'm in totally over my head here. I'm hoping someone can help me out.
>>
>> I've got 2 external (reference) documents I'm including into my
>> stylesheet.
>>
>> One is a list of staff. It looks like this (edited for brevity):
>>
>> <people>
>> <staff staff_id="123456789" alpha_key="A" sort_key="AberyBrian">
>> <display_name>Brian H Abery</display_name>
>> </staff>
>> <staff staff_id="987654321" alpha_key="A" sort_key="AlbusDeb">
>> <display_name>Deb Albus</display_name>
>> </staff>
>> <staff staff_id="456321789" alpha_key="A" sort_key="AltmanJason">
>> <display_name>Jason R Altman</display_name>
>> </staff>
>> </people>
>>
>> And the other is the three way join between staff, projects and roles
>> <project_staff_roles>
>> <project_staff_role project_id="1" staff_id="123456789"
>> role_id="staff">
>> <staff staff_id="123456789" alpha_key="A" sort_key="AberyBrian">
>> <display_name>Brian H Abery</display_name>
>> </staff>
>> </project_staff_role>
>> <project_staff_role project_id="1" staff_id="123456789"
>> role_id="director">
>> <staff staff_id="123456789" alpha_key="A" sort_key="AberyBrian">
>> <display_name>Brian H Abery</display_name>
>> </staff>
>> </project_staff_role>
>> <project_staff_role project_id="2" staff_id="987654321"
>> role_id="staff">
>> <staff staff_id="987654321" alpha_key="A" sort_key="AlbusDeb">
>> <display_name>Deb Albus</display_name>
>> </staff>
>> </project_staff_role>
>> </project_staff_roles>
>>
>> I want to break this into two groups based on the current project_id.
>> So if I'm viewing project_id=1
>> I want two groups of people
>>
>> Project Staff:
>> <people>
>> <staff staff_id="123456789" alpha_key="A" sort_key="AberyBrian">
>> <display_name>Brian H Abery</display_name>
>> </staff>
>> </people>
>>
>> Non-Project-Staff
>> <people>
>> <staff staff_id="987654321" alpha_key="A" sort_key="AlbusDeb">
>> <display_name>Deb Albus</display_name>
>> </staff>
>> <staff staff_id="456321789" alpha_key="A" sort_key="AltmanJason">
>> <display_name>Jason R Altman</display_name>
>> </staff>
>> </people>
>>
>> I've got the following variables in my document:
>> <xsl:variable name="staff" select="document($ref_staff)/people"/>
>> <xsl:variable name="staff_roles"
>> select="document($ref_project_staff_role)/project_staff_roles/project_staff_role[@role_id='staff']"/>
>>
>> <xsl:variable name="project_staff"
>> select="$staff_roles[@project_id=$[project_id]/staff"/>
>> <xsl:variable name="non_project_staff" select="?????"/>
>>
>> How do I even go about thinking about this? I've tried googling it but
>> I have no idea what to search on. I've tried various iterations of
>> keys, etc but I just can't get it.
>>
>> The final xslt that gives the desired output is:
>> <xsl:if test="count($project_staff) > 0">
>> <fieldset class="span-18 last col-wrap">
>> <legend class="quiet">
>> <xsl:value-of
>> select="ancestor::project/associates/associate/title"/>
>> People</legend>
>> <xsl:call-template name="layout_3column">
>> <xsl:with-param name="objects"
>> select="$project_staff"/>
>> </xsl:call-template>
>> </fieldset>
>> </xsl:if>
>> <xsl:if test="count($non_project_staff) > 0">
>> <fieldset class="span-18 last col-wrap">
>> <legend class="quiet">All Other People</legend>
>> <div id="tabs">
>> <ul>
>> <xsl:for-each
>>
>> select="$staff/staff/@alpha_key[generate-id()=generate-id(key('alpha',
>> .))]">
>> <xsl:if
>> test="count($non_project_staff[@alpha_key = current()]) > 0">
>> <xsl:call-template name="tab_link">
>> <xsl:with-param name="alpha_string"
>> select="."/>
>> </xsl:call-template>
>> </xsl:if>
>> </xsl:for-each>
>> </ul>
>> <xsl:for-each
>>
>> select="$staff/staff/@alpha_key[generate-id()=generate-id(key('alpha',
>> .))]">
>> <xsl:if
>> test="count($non_project_staff[@alpha_key = current()]) > 0">
>> <xsl:call-template name="tab_data">
>> <xsl:with-param name="alpha_string"
>> select="."/>
>> <xsl:with-param name="objects"
>>
>> select="$non_project_staff[@alpha_key = current()]"/>
>> </xsl:call-template>
>> </xsl:if>
>> </xsl:for-each>
>> </div>
>> </fieldset>
>> </xsl:if>
>>
>>
>> I hope this is clear. Any help would be much appreciated.
>>
>> Thanks in advance.
>> Joelle
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