Re: [xsl] A smarter choose operation XSL 1.1

[Karl Stubsjoen <kstubs@xxxxxxxxx>]

I am not worthy!
OK, I will give this a try, thanks!

On Wed, Jun 10, 2009 at 2:53 PM, Michael Kay<mike@xxxxxxxxxxxx> wrote:
> select="(1.0, 1.7, 2.25, 3.0)[count(($opt.one, $opt.two,
$opt.three)[.])+1]"
>
> The strange predicate [.] selects items in the sequence that are true.
>
> Regards,
>
> Michael Kay
> http://www.saxonica.com/
> http://twitter.com/michaelhkay
>
>> -----Original Message-----
>> From: Karl Stubsjoen [mailto:kstubs@xxxxxxxxx]
>> Sent: 10 June 2009 22:20
>> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
>> Subject: [xsl] A smarter choose operation XSL 1.1
>>
>> I have 3 optional param values that are either true/false.  I
>> need a solution which will return 4 different numbers when:
>>
>> 1) all param values are true
>> 2) two param values are true
>> 3) one param value is true
>> 4) none are true
>>
>> I was about to write one big choose and then thought maybe
>> there is a more efficient way of doing it.  So any ideas on
>> this one?  For sake of discussion, here is a mock up of the
>> template and param values I
>> have:
>>
>> <xsl:template name="test">
>>   <xsl:param name="optional.one" select="true()" />
>>   <xsl:param name="optional.two" select="true()" />
>>   <xsl:param name="optional.three" select="true()" />
>>
>>   <!--
>>     Return:
>>
>>     When All, return 3.00
>>     When Two, return 2.25
>>     When One, return 1.70
>>     When Zero, return 1.00
>>    -->
>>
>> </xsl:template/>
>>
>> Thanks for the help!
>>
>> Karl..