Re: [xsl] A smarter choose operation XSL 1.1

[DavePawson <davep@xxxxxxxxxxxxx>]

Michael Kay wrote:
> select="(1.0, 1.7, 2.25, 3.0)[count(($opt.one, $opt.two, $opt.three)[.])+1]"
>
> The strange predicate [.] selects items in the sequence that are true.

Would someone expand on this oddity please?
I'm guessing 'true' in this case is the xslt version of 'true'...
I.e. non-empty?

How does that relate to
($opt.one, $opt.two, $opt.three)[.]  please?

You make it look like a subscript into an array Mike?

regards DaveP

> Regards,
>
> Michael Kay
> http://www.saxonica.com/
> http://twitter.com/michaelhkay  
>
> > -----Original Message-----
> > From: Karl Stubsjoen [mailto:kstubs@xxxxxxxxx] 
> > Sent: 10 June 2009 22:20
> > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> > Subject: [xsl] A smarter choose operation XSL 1.1
> >
> > I have 3 optional param values that are either true/false.  I 
> > need a solution which will return 4 different numbers when:
> >
> > 1) all param values are true
> > 2) two param values are true
> > 3) one param value is true
> > 4) none are true
> >
> > I was about to write one big choose and then thought maybe 
> > there is a more efficient way of doing it.  So any ideas on 
> > this one?  For sake of discussion, here is a mock up of the 
> > template and param values I
> > have:
> >
> > <xsl:template name="test">
> >   <xsl:param name="optional.one" select="true()" />
> >   <xsl:param name="optional.two" select="true()" />
> >   <xsl:param name="optional.three" select="true()" />
> >
> >   <!--
> >     Return:
> >
> >     When All, return 3.00
> >     When Two, return 2.25
> >     When One, return 1.70
> >     When Zero, return 1.00
> >    -->
> >
> > </xsl:template/>
> >
> > Thanks for the help!
> >
> > Karl..



regards

--
Dave Pawson
XSLT XSL-FO FAQ.
http://www.dpawson.co.uk