[xsl] question on random numbers for browser XSLT

Subject: [xsl] question on random numbers for browser XSLT
From: Hermann Stamm-Wilbrandt <STAMMW@xxxxxxxxxx>
Date: Wed, 22 Jul 2009 14:43:03 +0200
I want random numbers in a stylesheet but I am bound to XSLT 1.0 and
not able to make use of "http://exslt.org/random"; extensions because
the stylesheet should be accessed by <?xml-stylesheet ...?> in a
browser XML document.

Is there a pure XSLT solution?
(the quality of the generated random numbers is not that important)


After some playing around I found below (not pure XSLT) solution.
Important is that the PERL script lives in the same domain as the
stylesheet. You may try it out (random number "0-5") by clicking here:
http://stamm-wilbrandt.de/en/xsl-list/random/rand6.xml


$ cat rand6.xml
<?xml version="1.0" encoding="ISO-8859-1"?>
<?xml-stylesheet type="text/xsl" href="rand6.xsl"?>
<tag/>

$ cat rand6.xsl
<xsl:stylesheet
  version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
  <xsl:output method="html" encoding="UTF-8"/>

  <xsl:template match="/">
    <xsl:variable name="rand"
      select="document('/cgi-bin/rand.pl?6')"/>
    <html><body>rand(6): <xsl:value-of select="$rand"/></body></html>:
  </xsl:template>

</xsl:stylesheet>
$

$ cat cgi-bin/rand.pl
#!/usr/bin/perl -w.

print "Content-type: text/xml\n\n";

printf("<?xml version=\"1.0\"?>\n");
printf("<rand>%d</rand>\n", rand($ARGV[0]));
printf("<!-- PERL rand(%d) -->\n",$ARGV[0]);


Mit besten Gr|_en / Best wishes,

Hermann Stamm-Wilbrandt
Developer, XML Compiler
WebSphere DataPower SOA Appliances
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