Re: [xsl] How to strip all optional but empty elements from a XML doc?

Subject: Re: [xsl] How to strip all optional but empty elements from a XML doc?
From: Michael Ludwig <mlu@xxxxxxxxxxxxx>
Date: Tue, 04 Aug 2009 08:28:20 +0200
Ben Stover schrieb:
Assume I have a XML doc and a XSD schema file which defines mandatory
and optional element fields.

How can I now go recursively through the whole XML document

Recursion is free, as it is down by default.

and find all elements which are optional (e.g. minoccurs=0)

That information is in XSD. I might be wrong, but I don't think it is exposed in the XPath 2.0 Data Model with XSD annotations enabled. You might get a list of the optional elements by (1) reading the schema, (2) grepping the schema, or processing Saxon's normalized XSD representation.

but currently EMPTY.

"Empty" might need a better definition. I'll take it to mean the absence of nodes on the child axis, without taking the attribute axis into account.

These empty, optional elements should be stripped off so that the
resulting XML does not contain them any more.

Strippging is achieved by defining null template rules as follows.

<xsl:stylesheet version="1.0"

  <xsl:template match="eins[not(node())]"/>
  <xsl:template match="zwei[not(node())]"/>
  <xsl:template match="drei[not(node())]"/>

  <xsl:template match="@*|node()"><!-- identity template -->
    <xsl:copy><xsl:apply-templates select="@*|node()"/></xsl:copy>


Michael Ludwig

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