Subject: Re: [xsl] How to replace a reference to a tag by the tag itself? From: David Carlisle <davidc@xxxxxxxxx> Date: Thu, 6 Aug 2009 13:49:35 +0100 |
well doing a full job is complicated as the actual schema may be skattered opver multiple xml files, but assuming that isn't thecase, something like <xsl:key name="g" match="xsd:group[@name]" use="@name"/> then <xsl:template match="xsd:group[@ref]"> <xsl:apply-templates select="key('g',@ref)/*"/> </xsl:template> together with an identity template to copy the rest of the stuff. Of course xslt never handles tags, despite the subject line. David ________________________________________________________________________ The Numerical Algorithms Group Ltd is a company registered in England and Wales with company number 1249803. The registered office is: Wilkinson House, Jordan Hill Road, Oxford OX2 8DR, United Kingdom. This e-mail has been scanned for all viruses by Star. The service is powered by MessageLabs. ________________________________________________________________________
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