Subject: RE: [xsl] how to keep context when copying From: "Michael Kay" <mike@xxxxxxxxxxxx> Date: Tue, 18 Aug 2009 15:02:47 +0100 |
> <xsl:function name="fdx:GetDef"> > <xsl:param name="ref"/> > <xsl:copy-of select="key('keyItems', $ref/@OID)"/> </xsl:function> > > My problem is that the nodes returned by this function lack > ancestor info that would be useful in downstream processing > of the node. Is there a way that I can rewrite the function > to return a node that allows me to get at the node's > ancestors for example. Just return the node itself, instead of making a copy. <xsl:sequence select="key('keyItems', $ref/@OID)"/> Regards, Michael Kay http://www.saxonica.com/ http://twitter.com/michaelhkay
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