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Subject: RE: [xsl] how to keep context when copying From: "Michael Kay" <mike@xxxxxxxxxxxx> Date: Tue, 18 Aug 2009 15:02:47 +0100 |
> <xsl:function name="fdx:GetDef">
> <xsl:param name="ref"/>
> <xsl:copy-of select="key('keyItems', $ref/@OID)"/> </xsl:function>
>
> My problem is that the nodes returned by this function lack
> ancestor info that would be useful in downstream processing
> of the node. Is there a way that I can rewrite the function
> to return a node that allows me to get at the node's
> ancestors for example.
Just return the node itself, instead of making a copy.
<xsl:sequence select="key('keyItems', $ref/@OID)"/>
Regards,
Michael Kay
http://www.saxonica.com/
http://twitter.com/michaelhkay
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