Re: [xsl] generate an element only if the result is not empty

Subject: Re: [xsl] generate an element only if the result is not empty
From: Manuel Souto Pico <manuel.souto@xxxxxxxxxxxxxx>
Date: Tue, 25 Aug 2009 17:51:17 +0200
Hi again, David,

I'm fiddling with the code you sent this morning. Could you explain what exactly the following line does?

<xsl:template match="element[*]"/>

Thanks a lot!
Manuel


David Carlisle wrote:
The template (using select="node()" and not select=".")

    <xsl:template match="seg">
        <term>
            <xsl:value-of select="node()" />

That's a very strange construct to use, especially in xslt 1.

node() selects all the children and then value-of discards all but the
first, which means that if there are child elements as in your example
you get just the first indentation white space if there is any, however
if the first child had not been indented you would get the string value
of the first element.

<seg>
<it>&lt;/Title&gt;</it>
<bpt i="1" type="struct">&lt;Elt type='Groupbox' id='242' coor='0,0,412,112' style='50020007,0' class='#FF#0080'&gt;</bpt>
</seg>


produces

<term>
                </term>

but

<seg><it>&lt;/Title&gt;</it>
<bpt i="1" type="struct">&lt;Elt type='Groupbox' id='242' coor='0,0,412,112' style='50020007,0'
class='#FF#0080'&gt;</bpt></seg>


produces

<term>>&lt;/Title&gt;</term>

If I understand your requirement it is to ignore any seg elements with
element content, but to make a term element for those that have non
white space text content.

so just

<xsl:apply-templates select="seg"/>

with

<xsl:template match="seg[*]"/>

<xsl:template match="seg[not(normalize-space(.))]"/>

<xsl:template match="seg">
 <text><xsl:value-of select="."/></text>
</xsl:template>

David

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