Subject: [xsl] xsl:apply-templates in combination with xsl:choose From: Stefanie Haupt <st.haupt@xxxxxxxxx> Date: Wed, 26 Aug 2009 13:57:02 +0200 |
Hi! I'm stuck on a problem quite a while now and am glad for help. I'm trying to convert multiple input documents. They are have a highly different structure so I'm trying to let xslt divide them before they get processed further (using oxygenxml with built-in SAXON8B). I have a xml which holds the list of documents this way: <filesystem> <file>filename1.xml</file> <file>filename2.xml</file> <file>filename3.xml</file> <file>filename4.xml</file> </filesystem> and a xsl that matches first on filesystem, gives a list of the files and then I try to separate the files depending on something the contain or not: <xsl:template match="filesystem"> ..... <xsl:choose> <xsl:when test="file/document(.)/xh:html/xh:head/xh:link/attribute::rel[contains(.,'stylesheet')]"> <xsl:apply-templates select="file" mode="neuerTest"/> </xsl:when> <xsl:when test="file/document(.)/xh:html/xh:head/xh:title[contains(.,'Mag')]"> <xsl:apply-templates select="file" mode="#default"/> </xsl:when> </xsl:choose> </xsl:template> <xsl:template match="file" mode="neuerTest"> ... <xsl:template> <xsl:template match="file" mode="#default"> ... <xsl:template> The problem is that the first 'when' always turns true. So all files are processed using the first argument. I tried testing for the other type in first place and got the same result: The test I place first is always true even if I made sure that in the documents to be processed the things I test for are exclusive. Type B doesn't have a stylesheet attribute and type A never contains 'Mag' in title. There must be a syntactical error or am I using this at the wrong place? There must be something evident that I am missing. Can you please help me? I tried to keep this mail short if I left out something important, please drop me a line. Many thanks for any help! Stefanie
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