Re: [xsl] xsl-for-each-group in xslt 2.0

[Andrew Welch <andrew.j.welch@xxxxxxxxx>]

2009/9/28 a kusa <akusa8@xxxxxxxxx>:
> Hi
>
> I am having difficulties implementing xsl-for-each-group in xslt 2.0
>
> My XML is as follows:
>
> <list1>
> <listitem>A</listitem>
> <listitem>B</listitem>
> <list2>
> <listitem>C</listitem>
> <listitem>D</listitem>
> </list2>
> </list1>
>
> Every <listX><listitem> combination corresponds to one step.
>
> So I want this to transform into:
>
> <step1>A B</step1>
> <step2>C D</step2>
>
> I tried
>
> <xsl template match="list1">
>
> <xsl:-for-each-group select="." group-by="listitem">
> <step1><xsl:apply-templates/></step1>
>
> </xsl:for-each-group>
> <xsl:template>
>
> Can someone please help me understand where i am going wrong here?

It's not actually a grouping problem, the following templates will
give the output you want:

<xsl:template match="list1">
  <step1>
    <xsl:value-of select="listitem"/>
  </step1>
  <xsl:apply-templates select="list2"/>
</xsl:template>

<xsl:template match="list2">
  <step2>
    <xsl:value-of select="listitem"/>
  </step2>
  <xsl:apply-templates select="list3"/>
</xsl:template>

If the nesting depth is unknown you can modify that to be a single
template with name tests...


-- 
Andrew Welch
http://andrewjwelch.com
Kernow: http://kernowforsaxon.sf.net/