Subject: [xsl] How to copy only the really existing <choice> branch/element? "value-of-if-exist" From: "Ben Stover" <bxstover@xxxxxxxxxxx> Date: Wed, 07 Oct 2009 14:09:59 +0200 |
Assume I have a XML source based on the following (simplified) XSD schema: <xsd:element name="top" type="mytype"/> <xsd:complexType name="mytype"> <xsd:choice> <xsd:element name="aaa" type="....."> <xsd:element name="bbb" type="....."> <xsd:element name="ccc" type="....."> </xsd:choice> </xsd:complexType> That mean either element aaa or element bbb or element ccc is filled/exists. Now I want to copy only this sub-element to a target which currently exists. If I simply write: <xsl:value-of select=".../aaa"/> <xsl:value-of select=".../bbb"/> <xsl:value-of select=".../ccc"/> then ALL three elements were copied. The 2 branches which do not exist were created as empty elements so that the target XML doc looks like e.g. <top> <aaa></aaa> <bbb>myvalue</bbb> <ccc></ccc> </top> which is an invalid XML because of its XSD schema file definition. The question is now: How can I let XSL copy only this branch/element which really exists? I need a function like <xsl:value-of-only-the-existing-choice-branch select=..../top"/> or <xsl:value-of-if-exists select=".../aaa"/> <xsl:value-of-if-exists select=".../bbb"/> <xsl:value-of-if-exists select=".../ccc"/> How can I do this in detail? Thank you Ben
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