Re: [xsl] XPath problem with getting all ancestors

[Jostein Austvik Jacobsen <josteinaj@xxxxxxxxx>]

The actual template does more than copying; it uses recursion to group  
sections started by headlines at different levels defined by its  
attributes. I got it from this post:
http://www.biglist.com/lists/lists.mulberrytech.com/xsl-list/archives/200910/msg00228.html

The function works really well (except for cases when a headline level  
is skipped). So if its possible to keep copying the nodes it would be  
great; otherwise I'll have to fix the function (I'm thinking of  
expanding the recursion into four xls:for-each-group statements - it's  
not allowed to go deeper anyway).

I'll do sone further testing once I get back to the computer.

Regards
Jostein

Den 23. okt. 2009 kl. 15.20 skrev "Michael Kay" <mike@xxxxxxxxxxxx>:

> >    <xsl:template match="article">
> >        <xsl:variable name="v1">
> >            <xsl:copy-of select="content/node()"/>
> >        </xsl:variable>
> >        <xsl:sequence select="mf:group($v1/node())"/>
> >    </xsl:template>
>
> As I suspected, you are copying the nodes, and the copies do not  
> have the
> same ancestors.
>
> It's not clear to me WHY you are copying them - it seems quite  
> unnecessary.
>
> Regards,
>
> Michael Kay
> http://www.saxonica.com/
> http://twitter.com/michaelhkay