RE: [xsl] how to exclude namespaces from copy-of

["Michael Kay" <mike@xxxxxxxxxxxx>]

Although xsl:copy-of in XSLT 2.0 can exclude unused namespaces
(copy-namespaces="no"), it can't remove declarations of namespaces that are
actually in use. You don't actually want to make a copy of the data, you
want to transform it by changing the names of the elements. Remember that
the difference between <rss/> and <rss xmlns="xyz"/> is not just a namespace
declaration - the two elements have different names. So you need to do a
"renaming identity transform" along the lines

<xsl:template match="*">
  <xsl:element name="{local-name()}">
    <xsl:apply-templates select="*"/>
  </xsl:element>
</xsl:template>

Regards,

Michael Kay
http://www.saxonica.com/
http://twitter.com/michaelhkay  

> -----Original Message-----
> From: cert21 [mailto:cert21@xxxxxxx] 
> Sent: 05 November 2009 15:13
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: [xsl] how to exclude namespaces from copy-of
> 
> Hello!
> 
> I am trying to parse the atom feed using the xsl template.
> 
> The item in the feed contains this element: (example) <div 
> xmlns="http://www.w3.org/1999/xhtml"; 
> xmlns:dc="http://purl.org/dc/elements/1.1/"; 
> xmlns:thr="http://purl.org/syndication/thread/1.0";>
> <p>
> October and November are busy months for Amazon Web 
> Services!</p> </div>
> 
> I want to copy the div with all its child elements, so I use 
> copy-of The problem is that I don't want the 
> xmlns="http://www.w3.org/1999/xhtml";
> or xmlns:dc or any other extra data in the div attribute
> 
> I just want the result to be
> <div>
> <p>
> October and November are busy months for Amazon Web 
> Services!</p> </div>
> 
> How can I do this?
> 
> Thank you.