RE: [xsl] for-each tokenize() and context problem

["Mario Madunic" <Mario_Madunic@xxxxxxxxxxxx>]

Thanks Martin, it worked like a charm.

For clarification,

Any for-each that is a descendant of a for-each (with no parent for-each) will
lose its context. The context will be the current node, in this case text. Am
I correct in this assumption?

Would the same be true of if I for-each'd an element with child nodes and then
for-each'd the child nodes (it contains child nodes). I'm assuming that the
child for-each will only have context to descendants and not ancestors.
Hopefully that made sense.

Thanks again Martin for the quick and helpful reply.

Marijan (Mario) Madunic
Publishing Specialist
New Flyer Industries

-----Original Message-----
From: Martin Honnen [mailto:Martin.Honnen@xxxxxx]
Sent: Thursday, November 19, 2009 11:33 AM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: Re: [xsl] for-each tokenize() and context problem

Mario Madunic wrote:
> I have the following variable,

Put an
   <xsl:variable name="t" select="."/>
here, then

> <xsl:variable name="l_GetPartNumber">
>   <xsl:for-each select="tokenize(normalize-space($l_Components), ' ')">
>     <xsl:variable name="l_Num" select="." />
>     <xsl:for-each select="ancestor::*[self::page]/row[entry[1] =
$l_Num]/entry[3]">

here use
       <xsl:for-each select="$t/ancestor::*[self::page]/row[entry[1] =
$l_Num]/entry[3]">

That is necessary as with the for-each select="tokenize(...)" you no
longer have the context node you have outside of the for-each.




--

	Martin Honnen
	http://msmvps.com/blogs/martin_honnen/


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