Re: [xsl] Copy the Document Type Definition of XML file

Subject: Re: [xsl] Copy the Document Type Definition of XML file
From: Andrew Welch <andrew.j.welch@xxxxxxxxx>
Date: Tue, 15 Dec 2009 09:42:13 +0000
2009/12/15 Rossen Kovachev <kovachev@xxxxxxxx>:
> Hi!
> I'm trying to copy resp. to modify an XML document via XSL. Here I use
> the usual identity template:
> <xsl:template match="@*|node()">
>  <xsl:copy>
>    <xsl:apply-templates select="@*|node()"/>
>  </xsl:copy>
> </xsl:template>
> Unfortunately the DTD definition of the source document is not copied at
> this way.
> Does anybody know how can I accomplish this?

I would say that unless you absolutely have to, don't bother.  If you
need the XML validated again at a subsequent step then do it in that
step, rather than each and every time the XML is parsed...

If you do really have to :) then you could use LexEv
( which will add the values as
processing instructions to the input, for example:

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"

will become:

<?doctype-public -//W3C//DTD XHTML 1.0 Transitional//EN?>

which you can then use like this:


LexEv is also part of Kernow, so to try this out just enable it in the

Andrew Welch

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