Subject: [xsl] convert xml with schema to html with xslt From: Lajos Joo <lajosjoo@xxxxxxxxx> Date: Mon, 21 Dec 2009 02:21:06 -0800 (PST) |
Hello! I have a problem. I have a small xml file which has a schema declaration in the root element. I cannot convert it to html with an xslt file. If i remove the schema declaration the conversion is fine. Please suggest me how to correct this. I have included a shcema import but it didnt help: <xsl:import-schema namespace="urn:Verlag" schema-location="urn:Verlag http://192.168.190.181:8879/xml/STRUKTUR.xsd" /> The xml file looks like this: <LOSCHNIGG xmlns="urn:Verlag" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="urn:Verlag http://192.168.190.181:8879/xml/STRUKTUR.xsd"> <metadaten> <gilt-ab>1000-01-01</gilt-ab> <gilt-bis>9999-12-31</gilt-bis> <Fassung_Publikation> <Publikationsstand>2009-12-19</Publikationsstand> <Release_Version>1</Release_Version> </Fassung_Publikation> </metadaten> <para> text... </para> </LOSCHNIGG> The xml works fine and the xsd is in the right place. The xsl looks like this: <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns="http://www.w3.org/1999/xhtml" version="2.0"> <!-- <xsl:import-schema namespace="urn:Verlag" schema-location="urn:Verlag http://192.168.190.181:8879/xml/STRUKTUR.xsd" />--> <xsl:output encoding="UTF-8" indent="yes" method="html" version="1.0" /> <xsl:template match="@*|node()"> <xsl:copy> <xsl:apply-templates select="@*|node()"/> </xsl:copy> </xsl:template> <xsl:template name="paragraph" match="para"> <xsl:element name="p"> <xsl:apply-templates/> </xsl:element> </xsl:template> <xsl:template match="/"> <xsl:element name="html"> <xsl:element name="head"> <xsl:element name="title">Preview</xsl:element> </xsl:element> <xsl:apply-templates/> </xsl:element> </xsl:template> </xsl:stylesheet> Thank you! Lajos
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